7_Ch 18 College Physics ProblemCH18 Direct-Current Circuits

7_Ch 18 College - Direct-Current Circuits 18.4 a(a The current through this series combination is I= V)bc Rbc = b 9.0 W 12 V = 2.0 A 6.0 Therefore

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Direct-Current Circuits 105 18.4 (a) The current through this series combination is () 12 V 2.0 A 6.0 bc bc V I R == = ( Therefore, the terminal potential difference of the power supply is ) 9.0 6.0 30 V eq VI R ∆= = + Ω= (b) When connected in parallel, the potential difference across either resistor is the voltage setting of the power supply. Thus, 99 0.25 A 9.0 2.3 V VIR = 18.5 (a) The equivalent resistance of the two parallel resistors is 1 11 4.12 7.00 10.0 p R  =+ =  ΩΩ 
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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