Reflection and Refraction of Light23922.4(a) The time for the light to travel to the stationary mirror and back is ( )3482 35.010 m22.3310s3.0010 m sdtc−×∆===××At the lowest angular speed, the octagonal mirror will have rotated 1in this time, so 8 revmin418 rev536 rev s2.3310stθω−∆===∆×(b) At the next higher angular speed, the mirror will have rotated 28 rev intheelapsed time, or ( )32min22 536 rev s1.0710 rev sωω=×22.5(a) For the light beam to make it through both slots, the time for the light to travel
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.