7_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

7_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 273 23.6 The lateral magnification is given by M qp = − . Therefore, the image distance is ( ) () 0.013 0 30.0 cm cm qM p =− 0.390 The mirror equation: 211 Rpq =+ or 2 pq R p q = + gives ( ) 2 30.0 cm 0.790 cm 390 cm R == 0.390 cm 30.0 cm 0. The negative sign tells us that the surface is convex. The magnitude of the radius of curvature of the cornea is 0 7.90 mm R .790 cm 23.7 The radius of curvature of a concave mirror is positive, so R 20.0 cm = + . The mirror equation then gives 10.0 cm 121 1 1 10.0 cm 10.0 cm p qRp p p =−= −= , or ( )
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