7_Ch 24 College Physics ProblemCH24 Wave Optics

# 7_Ch 24 College - Wave Optics 24.5(a From d sin = m the angle for the m = 1 maximum for the sound waves is m v m = sin 1 sound d d f = sin 1 354 m

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Wave Optics 309 24.5 (a) From d sin m θ λ = , the angle for the 1 m = maximum for the sound waves is 11 1 354 m s 1 sin 36.2 0.300 m 2 000 Hz sound v mm dd −−   = =     sin θλ == sin f ° (b) For 3.00-cm microwaves, the required slit spacing is () ( ) 13 . 0 0 cm 5.08 cm sin sin36.2 m d = ° (c) The wavelength is sin d m = ; and if this is light, the frequency is ( ) ( ) 8 14 -6 . 0 01 0 m s 5.08 10 Hz sin 1.00 10 m sin36.2 mc c f d λθ × = = × ×° 24.6 The position of the first order bright fringe for wavelength is 1 L y d = Thus, ( ) ( ) 9 1 3 700 400 10 m 1.5 m 1.5 1 m 1.5 mm 0.30 10 m L y d −× ∆= = = × = × 3 0 24.7 Note that, with the conditions given, the small angle
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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