{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

8_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

8_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
208 CHAPTER 21 21.15 The ratio of inductive reactance at 2 50.0 Hz f = to that at 1 60.0 Hz f = is ( ) ( ) 2 2 2 1 1 1 2 2 L L X f L f X f L π π = = f , so ( ) ( ) ( ) 54.0 45.0 2 2 1 1 50.0 Hz 60.0 Hz L L f X X f = = Ω = 50.0 Hz The maximum current at 2 f = is then ( ) ( ) rms L L V X X = max max 2 2 100 V 3.14 A 45.0 V I = = = 21.16 The maximum current in this inductive circuit will be ( ) ( ) ( ) rms rms max rms 2 2 2 2 L V V I I X f π = = = max 80.0 mA I < L Thus, if , it is necessary that ( ) ( ) ( ) ( ) ( ) rms 2 2 80.0 mA V f π 2 2 50.0 V or 7.03 H 2 20.0 Hz 8.00 10 A L L π > = > × 21.17 From B N I Φ = L , the total flux through the coil is , B total B N L I Φ = Φ = where is the flux through a single turn on the coil. Thus, B Φ
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}