274CHAPTER 23 23.8(a) Since the object is in front of the mirror, . With the image behind the mirror, . The mirror equation gives the radius of curvature as 0p>0q<2111111.00 cm10.0 cm10.0Rpq=+=−=0-1cmor 10.0 cm22.22cm9==+R(b) The magnification is ( )10.0 cm10.01.00 cmqMp−=−= +23.9The cylindrical wall is a highly efficient mirror for sound, with radius of curvature, . In a vertical plane the sound disperses as usual but that radiated in a horizontal plane is concentrated in a sound image at distance qfrom the back of the niche, where 2.50 mR=121212.50 m2.00 mqRp−, which gives 3.33 mq=23.10The image was initially upright but became inverted when Dina was more than 30 cm
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