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8_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

# 8_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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274 CHAPTER 23 23.8 (a) Since the object is in front of the mirror, . With the image behind the mirror, . The mirror equation gives the radius of curvature as 0 p > 0 q < 2 1 1 1 1 1 1.00 cm 10.0 cm 10.0 R p q = + = = 0-1 cm or 10.0 cm 2 2.22 cm 9 = = + R (b) The magnification is ( ) 10.0 cm 10.0 1.00 cm q M p = − = − = + 23.9 The cylindrical wall is a highly efficient mirror for sound, with radius of curvature, . In a vertical plane the sound disperses as usual but that radiated in a horizontal plane is concentrated in a sound image at distance q from the back of the niche, where 2.50 m R = 1 2 1 2 1 2.50 m 2.00 m q R p = = , which gives 3.33 m q = 23.10 The image was initially upright but became inverted when Dina was more than 30 cm
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