8_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

8_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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274 CHAPTER 23 23.8 (a) Since the object is in front of the mirror, . With the image behind the mirror, . The mirror equation gives the radius of curvature as 0 p > 0 q < 211 1 1 1 1.00 cm 10.0 cm 10.0 Rpq = + =−= 0 - 1 cm or 10.0 cm 22 . 2 2 c m 9  == +   R (b) The magnification is ( ) 10.0 cm 10.0 1.00 cm q M p =− = + 23.9 The cylindrical wall is a highly efficient mirror for sound, with radius of curvature, . In a vertical plane the sound disperses as usual but that radiated in a horizontal plane is concentrated in a sound image at distance q from the back of the niche, where 2.50 m R = 121 2 1 2.50 m 2.00 m qRp , which gives 3.33 m q = 23.10 The image was initially upright but became inverted when Dina was more than 30 cm
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