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Induced Voltages and Inductance
183
20.18
From
Bv
ε
=
, the required speed is
A
()
(
)
( )
0.500 A
6.00
1.00 m s
2.50 T
1.20 m
v
Ω
=
AA
IR
BB
===
20.19
⊥
=
A
v
G
, where
is the component of the magnetic field perpendicular to the velocity
. Thus,
B
⊥
() ()
( )
6
50.0
0
T sin58.0
60.0 m
300 m s
0.763 V
1
−
°
=
=×
20.20
The speed of the beam after falling freely for 9.00 m, starting from rest
, is
0
0
y
v
=
( )
22
0
2
0
2
9.80 m s
9.00 m
13.3 m s
yy
y
vva
y
=+∆
=
+
−
−
=
Since the induced emf is
⊥
=
A
B
, where
⊥
is the component of the magnetic field
perpendicular to the velocity
v
G
, we find
( )
( )
63
18.0
10
T
13.3 m
2.87
10
V
2.87 mV
12.0 m
s
−−
=
20.21
(a) Observe that only the horizontal component,
B
h
, of Earth’s magnetic field is
effective in exerting a vertical force on charged particles in the antenna. For the
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics, Inductance

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