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9_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

# 9_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 275 23.11 The magnified , virtual images formed by a concave mirror are upright, so 0 M > . Thus, 5.00 cm 2.50 2.00 cm q h M p h = − = = = + ( , giving ) 2.50 2.50 3.00 cm q p = − = − + 7.50 cm = − The mirror equation then gives, 2.50 1 2 1 1 1 1 3.00 cm 7.50 cm 7.50 c f R p q 1 m = = + = = or 7.50 cm 1.50 f = = 5.00 cm 23.12 Realize that the magnitude of the radius of curvature, R , is the same for both sides of the hubcap. For the convex side, R R = − ; and for the concave side, R R = + . The object distance p is positive (real object) and has the same value in both cases. Also, we write the virtual image distance as q q = − in each case. The mirror equation then gives:
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