9_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

9_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 275 23.11 The magnified , virtual images formed by a concave mirror are upright, so 0 M > . Thus, 5.00 cm 2.50 2.00 cm q h M ph =− = = =+ ( , giving ) 2.50 2.50 3.00 cm qp + 7.50 cm The mirror equation then gives, 1211 1 1 3.00 cm 7.50 cm 7.50 c fRpq 1 m ==+= = or 7.50 cm 1.50 f == 5.00 cm 23.12 Realize that the magnitude of the radius of curvature, R , is the same for both sides of the hubcap. For the convex side, RR = − ; and for the concave side, . The object distance p is positive (real object) and has the same value in both cases. Also, we write the virtual image distance as qq = − in each case. The mirror equation then gives:
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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