Mirrors and Lenses27523.11The magnified, virtualimages formed by a concave mirror are upright, so 0M>. Thus, 5.00 cm2.502.00 cmqhMph′= −=== +(, giving )2.502.503.00 cmqp= −= −+7.50 cm= −The mirror equation then gives, 2.501211113.00 cm7.50 cm7.50 cfRpq1m−==+=−=or 7.50 cm1.50f==5.00 cm23.12Realize that the magnitude of the radius of curvature, R, is the same for both sides of the hubcap. For the convex side, RR= −; and for the concave side, RR= +. The object distance pis positive (real object) and has the same value in both cases. Also, we write the virtual image distance as qq= −in each case. The mirror equation then gives:
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