9_Ch 24 College Physics ProblemCH24 Wave Optics

# 9_Ch 24 College Physics ProblemCH24 Wave Optics - 311 Wave...

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Wave Optics 311 (a) The path difference is then () ( ) 3 sin 0.150 mm sin 0.737 1.93 10 mm 1.93 m d δθ µ == ° = × = (b) 6 9 1.93 10 m 3.00 643 10 m λ δ  =  ×  (c) Since the path difference for this position is a whole number of wavelengths, the waves interfere constructively and produce a maximum at this spot. 24.11 The distance between the central maximum (position of A) and the first minimum is 0 1 22 m LL ym dd = =+= Thus, 3.00 m 150 m 11.3 m 2 2 20.0 m L d y = 24.12 The path difference in the two waves received at the home is 2 30.0 km d =− where d is defined in the figure at the right. For minimum cloud height and (hence minimum path difference) to yield destructive interference, 2 = giving min 15.1 km d = 1 30.0 km
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