10_Ch 19 College Physics ProblemCH19 Magnetism

10_Ch 19 College Physics ProblemCH19 Magnetism - 150...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
150 CHAPTER 19 19.19 For the wire to move upward at constant speed, the net force acting on it must be zero. Thus, sin BIL mg θ = and for minimum field 90 = ° . The minimum field is ( ) ( ) () ( ) 2 0.015 kg 9.80 m s 0. 5.0 A 0.15 m mg B IL == = 20 T For the magnetic force to be directed upward when the current is toward the left, B must be directed out of the page . 19.20 The magnitude of the magnetic force exerted on a current-carrying conductor in a magnetic field is given by sin FB I = l , where B is the magnitude of the field, is the length of the conductor, I is the current in the conductor, and l is the angle the conductor makes with the direction of the field. In this case, ( )( )( ) ( ) 0.390 T 5.0 n 5.46 N sin
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online