10_Ch 20 College Physics ProblemCH20 Induced Voltages and Inductance

# 10_Ch 20 College Physics ProblemCH20 Induced Voltages and Inductance

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184 CHAPTER 20 20.22 During each revolution, one of the rotor blades sweeps out a horizontal circular area of radius A , 2 A π = A vertica BA B = . The number of magnetic field lines cut per revolution is . The induced emf is then B l A ∆Φ = () ( ) 2 5 2 3 5.0 10 T 3.0 m 2.8 10 V 2.8 mV 10 . 5 0 s ertical tf  ×  = = × = A v B B ε ∆Φ == 20.23 (a) To oppose the motion of the magnet, the magnetic field generated by the induced current should be directed to the right along the axis of the coil. The current must then be left to right through the resistor. (b) The magnetic field produced by the current should be directed to the left along the axis of the coil, so the current must be right to left through the resistor. 20.24 (a) As the bottom conductor of the loop falls, it cuts across the magnetic field lines coming out of the page. This induces an emf of magnitude Bwv = E in this conductor, with the left end at the higher potential. As a result, an induced current of magnitude Bwv I RR E flows clockwise around the loop. The field then exerts
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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