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10_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

10_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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276 CHAPTER 23 23.13 The image is upright, so 0 M > , and we have 2.0 q M p = − = + , or ( ) 2.0 2.0 25 cm 50 cm q p =− =− = − The radius of curvature is then found to be 2 1 1 1 25 c R p q 1 2 1 m 50 cm m 50 c = + = = , or 0.50 m 2 1.0 m +1 R = = 23.14 The ball is a convex mirror with 4.25 cm 2 diameter R = − = − Recall that a convex mirror can form only upright virtual images of real objects. Hence,
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