276CHAPTER 23 23.13The image is upright, so 0M>, and we have 2.0qMp=−=+, or ( )2.02.0 25 cm50 cmqp=−=−=−The radius of curvature is then found to be 211125 cRpq121m50 cmm50 c−=+=−=, or 0.50 m21.0 m+1R==23.14The ball is a convex mirror with 4.25 cm2diameterRRecall that a convex mirror can form only upright virtual images of real objects. Hence,
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.