Alternating Current Circuits and Electromagnetic Waves211(d) When the instantaneous current is a maximum ( )maxiI=, the instantaneous voltage across the resistor is 21.310=×max, maxVRRviRIRV∆===∆max=. Again, the instantaneous voltage across a capacitor is a quarter cycle out of phase with the current. Thus, when , we must have 0∆=Cvand ()0CCqCv=∆ =. Then, applying Kirchhoff’s loop rule to the instantaneous voltages around the series circuit at the instant when max=gives 21.310 V=×,max0sourceV∆ +RCvv∆+Rv∆=21.23( )( )2260.0 Hz0.400 H151 LXfLπ===Ω611882260.0 Hz3.0010FCXfC−×4 =Ω( )2260.0 151 RLCLCZRXX=+− =Ω+Ω−22884 736Ω=Ωand rmsrmsRLCVIZ∆=(a) 207LCLCXXX=+ −= − =
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.