11_Ch 25 College Physics ProblemCH25 Optical Instruments

11_Ch 25 College Physics ProblemCH25 Optical Instruments -...

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Optical Instruments 347 (b) With the image at the normal near point, the angular magnification is max 25.0 cm 25.0 cm 1 1 7.14 4.07 cm mm f == + = + = + 25.20 (a) For maximum magnification, the image should be at the normal near point ( ) 25.0 cm q =− of the eye. Then, from the thin lens equation, ( )( ) 25.0 cm 5.00 cm 4.17 cm 25.0 cm 5.00 cm qf p qf = + −− (b) The magnification is 25.0 cm 25.0 cm 11 5.00 cm m f =+ 6 . 0 0 25.21 (a) From the thin lens equation, a real inverted image is formed at an image distance of ( )( ) 71.0 cm 39.0 cm 86.5 cm 71.0 cm 39.0 cm pf q pf = + so the lateral magnification produced by the lens is 86.5 cm 1.22 71.0 cm q h M hp −= = and the magnitude is 1.22 M = (b) If
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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