12CHAPTER 15 Thus, Σ=and The resultant force on the 6.00 nC charge is then ()723cos45.03.8110NxFFF−+°=×8sin45.07.6310Ny−Σ= −°=−×()()2273.8910NRx y−=Σ +Σ=×at 1tan11.3yxFFθ−Σ==−°Σor 73.8910N at 11.3 below + axRx−=×°FGis 15.13The forces on the 7.00 µC charge are shown at the right. ( )( )(6629122292227.0010C2.0010CNm8.9910 C0.500 m0.503 N7.0010C4.0010C8.99C0.500 m1.01 NFF−−××⋅=⋅=(Thus, )12cos60.00.755 NxΣ= +°=sin60.00.436 Ny°=−and The resultant force on the 7.00
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.