80CHAPTER 17 17.23At 80°C, ()13005.0 V1200 10.510C80 C20 CVVIRRTTα−−∆∆===+−Ω+−×°°−°or 22.610A26 mAI−=×=17.24If , then 41.0 at 20 C and 41.4 at 29.0 C=Ω=°=Ω=°( )1TT=+−RRgives the temperature coefficient of resistivity of the material making up this wire as ( )1°C−3041.4 41.0 1.11041.0 29.0 C20°CRTT−−Ω−Ω=°−×17.25( )( )820621.710m10.0 m5.67103.0010mLRAρ−−−×Ω⋅= ××Ω(a) At ( )030.0 C, 1RT=° = + −0TTRgives a resistance of 13230.0 C20.0 C5.8910−−−° °−°=×0.056 7 13.910CR=Ω+×Ω(b) At ( )10.0 C, 1RTyields T110.0 C20.0 C5.4510−−°=×0.056 7 13.910CR+×Ω17.26
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.