Magnetism15319.26The resistance of the loop is ( )( )83421.7010m8.00 m1.36101.0010mLRAρ−−−×Ω⋅=== ××Ωand the current in the loop is 30.100 V73.51.3610VIR−A∆=sinNBIAThe magnetic field exerts torque τθ=on the loop, and this is a maximum when sin1=()( ). Thus, ( )2T73.5 A2.00 m118 N=max10.400mNBIA⋅19.27The magnitude of the force a proton experiences as it moves perpendicularly to a magnetic field is ( ) ( )sinsin 90.0FqvBevBevB+°=This force is always directed perpendicular to the velocity of the proton and will supply
This is the end of the preview. Sign up
access the rest of the document.