{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

13_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

13_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Mirrors and Lenses 279 (b) The ball and its image coincide when 0 p = and when 1 1 2 2 p p p + = = R , or 1.00 p R m = = From 2 0 1 2 y y y v t a t = + , with 0 0 y v = , the times for the ball to fall from to these positions are found to be 3.00 m p = ( ) ( ) 2 2.00 m 0.639 s = 2 2 9.80 y y a = = ( ) s m t and 2 2 3.00 m 0.782 9.80 m s t = = s 23.21 From 1 2 2 n n 1 n n p q R + = , with R , the image position is found to be ( ) 50.0 cm 2 1 1.00 38.2 cm 1.309 n q p n =− =− =− or the virtual image is 38.2 c the upper surface of the ice m below 23.22 For a plane refracting surface
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}