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Mirrors and Lenses
279
(b)
The ball and its image coincide when
0
p
=
and when
1
1
2
2
p
p
p
+
=
=
R
, or
1.00
p
R
m
=
=
From
2
0
1
2
y
y
y
v
t
a t
∆
=
+
, with
0
0
y
v
=
, the times for the ball to fall from
to
these positions are found to be
3.00 m
p
=
(
)
(
)
2
2.00 m
0.639
s
=
2
2
9.80
y
y
a
∆
−
=
=
−
(
)
s
m
t
and
2
2
3.00 m
0.782
9.80 m s
t
−
=
=
−
s
23.21
From
1
2
2
n
n
1
n
n
p
q
R
−
+
=
, with
R
→
∞
, the image position is found to be
(
)
50.0 cm
2
1
1.00
38.2 cm
1.309
n
q
p
n
=−
=−
=−
or the virtual image is
38.2 c
the upper surface of the ice
m below
23.22
For a plane refracting surface
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- Fall '10
- STAFF
- Physics, n1, image coincide
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