280CHAPTER 23 23.23Since the center of curvature of the surface is on the side the light comes from, 0R<giving . Then, 4.0 cmR=−122nnnn1pqR−+=becomes 1.001.004.q−=−1.501.500 cm4.0 cm−, or 4.0 cmq= −Thus, the magnification 12qpnhMhn′==−, gives ()121.504.0 cm3.8 mm1.00 4.0 cmnqhhnp−′=−2.5 mm=23.24Light scattered from the bottom of the plate undergoes two refractions, once at the top of the plate and once at the top of the water. All surfaces are planes ( )R→∞, so the image distance for each refraction is ( )21qnnp. At the top of the plate, 1B1B1.3338.00 cm6.42 cm1.66waterglassnqpnor the first image is 6.42 cm below the top of the plate. This image serves as a real object for the refraction at the top of the water, so the final image of the bottom of the plate is
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.