14_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

14_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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280 CHAPTER 23 23.23 Since the center of curvature of the surface is on the side the light comes from, 0 R < giving . Then, 4.0 cm R =− 122 nnnn 1 p qR += becomes 1.00 1.00 4. q = 1.50 1.50 0 cm 4.0 cm , or 4.0 cm q = − Thus, the magnification 1 2 q p   n h M hn == , gives () 1 2 1.50 4.0 cm 3.8 mm 1.00 4.0 cm nq hh np ′=−  2.5 mm = 23.24 Light scattered from the bottom of the plate undergoes two refractions, once at the top of the plate and once at the top of the water. All surfaces are planes ( ) R , so the image distance for each refraction is ( ) 21 qn n p . At the top of the plate, 1B 1B 1.333 8.00 cm 6.42 cm 1.66 water glass n qp n or the first image is 6.42 cm below the top of the plate. This image serves as a real object for the refraction at the top of the water, so the final image of the bottom of the plate is
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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