15_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

15_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 281 23.25 As parallel rays from the Sun ( ) object distance, p →∞ enter the transparent sphere from air ( ) 1 1.00 n = , the center of curvature of the surface is on the side the light is going toward (back side). Thus, R . It is observed that a real image is formed on the surface opposite the Sun, giving the image distance as 0 2 qR > = + . Then 12 nn 2 1 p += becomes 1.00 RR 0 2 2.00 which reduces to and gives 2 =− 2.00 n = 23.26 The wall of the aquarium is a plane ( ) R → ∞ refracting surface separating water and air . Thus, () 1 1.333 n = 2 1.00 n = 2 1 p gives the image position as 2 1 1.333 p n qp n    . When the object position changes by p , the change in the image position is 1.333 p q ∆= . The apparent speed of the fish is then given by
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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