Mirrors and Lenses28123.25As parallel rays from the Sun ( )object distance, p→∞enter the transparent sphere from air ( )11.00n=, the center of curvature of the surface is on the side the light is going toward (back side). Thus, R. It is observed that a real image is formed on the surface opposite the Sun, giving the image distance as 02qR>= +. Then 12nn21p−+=becomes 1.00RR02−2.00which reduces to and gives 2=−2.00n=23.26The wall of the aquarium is a plane ( )R→ ∞refracting surface separating water and air . Thus, ()11.333n=21.00n=21p−gives the image position as 211.333pnqpn. When the object position changes by p∆, the change in the image position is 1.333pq∆−∆=. The apparent speedof the fish is then given by
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.