{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

16_Ch 17 College Physics ProblemCH17 Current and Resistance

16_Ch 17 College Physics ProblemCH17 Current and Resistance...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
84 CHAPTER 17 17.36 (a) ( )( ) ( )( ) 5 90 W 1 h 90 J s 3 600 s 3.2 10 J = ⋅ = = = × P E t (b) The power consumption of the color set is ( ) ( ) ( ) 120 V 2.50 A 300 W V I = ∆ = = P Therefore, the time required to consume the energy found in (a) is 5 3 3.2 10 J 1 min 1.1 10 s 18 min 300 J s 60 s E t × = = = × = P 17.37 The energy input required is ( ) ( ) ( ) ( ) 5 1.50 kg 4 186 J kg C 50.0 C 10.0 C 2.51 10 J E mc T = = ⋅° ° ° = × 10.0 min 600 s t and, if this is to be added in ∆ = = , the power input needed is 5 2.51 10 J 419 W 600 s E t × = = = P ( ) The power input to the heater may be expressed as 2 V R = ∆ P ( ) , so the needed resistance is ( ) 2 2 120 V 34.4 419 W V R = =
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}