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16_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

# 16_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

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216 CHAPTER 21 21.32 ( ) ( ) 3 2 2 600 Hz 6.0 10 H 23 L X fL π π = = × = ( ) ( ) -6 1 1 11 2 2 600 Hz 25 10 F C X fC π π = = = × ( ) ( ) ( ) 2 2 25 23 11 L C Z R X X = + = + Ω − 2 2 28 = (a) ( ) rms , rms rms 10 V 25 9.0 V 28 R V V I R R Z = = Ω = = ( ) rms , rms rms 10 V 23 8.2 28 L L L V V I X X Z = = = Ω = V ( ) rms , rms rms 10 V 11 3.8 28 C C C V V I X X Z = = = Ω = V , rms , rms , rms No , 9.0 V 8.2 V 3 R L C V V V + ∆ + ∆ = + + ( ) ( ) .8 V 21 V 10 V = However, observe that if we take phases into account and add these voltages vectorially, we find ( ) ( ) 2 2 , rms , rms , rms 9.0 V 8.2 V R L C V V V + ∆ − ∆ = + 2 2 3.8 V 10 V = rms = ∆ V (b) The p is the greatest. No power losses occur in an
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