216CHAPTER 21 21.32()( )322600 Hz6.010H23 LXfLππ−==×=Ω-61111 22600 Hz2510 FCXfCπ=×Ω( )2225 23 11LCZRXX=+− = Ω+Ω−2228Ω=Ω(a) rms,rmsrms10 V25 9.0 V28 RVVIRRZ∆==Ω=Ω∆=rms10 V23 8.228 LLLVXXZ∆∆= ==Ω=ΩV rms10 V11 3.828 CCCVXXZ∆=Ω=ΩNo , 9.0 V8.2 V3RLCVVV∆+∆=++.8 V21 V10 V=≠However, observe that if we take phases into account and add these voltages vectorially, we find 9.0 V8.2 VRLCVVV∆−+3.8 V10 V−=rms=∆V(b) The pis the greatest. No power losses occur in an ideal capacitor or inductor. ower delivered to the resistor(c) 222rmsrms10 V25 3.3 W28 VIRRZ∆=Ω=
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.