16_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

16_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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282 CHAPTER 23 (b) () 11 1 1.44 1 18.0 cm 12.0 cm f  =−   16.4 cm f = 23.29 From the thin lens equation, 111 p qf + = , the image distance is found to be ( ) 20.0 cm 20.0 cm p fp q pf p == −− (a) If 40.0 p = , then and cm 40.0 cm q = 40.0 cm 1.00 40.0 cm q M p = − The image is real, in 40.0 cm beyond the lens verted, and (b) If 20.0 p = , q cm → ∞ No image formed. Parallel rays leave the lens. (c) When 10.0 p = , and cm 20.0 cm q ( ) 20.0 cm 2. .0 cm = + 00 10 q M p The image is virt d 20.0 cm in front of the lens
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