282CHAPTER 23 (b) ()1111.44118.0 cm12.0 cmf=−−−16.4 cmf=23.29From the thin lens equation, 111pqf+=, the image distance is found to be ( )20.0 cm20.0 cmpfpqpf p==−−(a) If 40.0p=, then and cm40.0 cmq=40.0 cm1.0040.0 cmqMp= −The image is real, in40.0 cm beyond the lensverted, and(b) If 20.0p=, qcm→ ∞No image formed. Parallel rays leave the lens. (c) When 10.0p=, and cm20.0 cmq( )20.0 cm2..0 cm= +0010qMp−The image is virtd 20.0 cm in front of the lens
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.