17_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

17_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

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Alternating Current Circuits and Electromagnetic Waves 217 21.34 (a) At resonance, X so the impedance will be L X = () C 2 LC XX 22 01 5 ZR R R =+ = =Ω (b) When X , we have L X = C 1 2 fL 2 fC π = which yields 6 11 41 Hz 2 20 . 2 0 H 7 5 1 0 F f LC == = × (c) The current is a maximum at resonance where the impedance has its minimum value of = . (d) At 60 f = , Hz ( )( ) 2 60 Hz 0.20 H 75 L X , 6 1 35 2 60 Hz 75 10 F C X = × , and ( ) 75 35 43 +Ω = 15 Z Thus, ( ) max rms 2 150 V 2.5 A 24 3 V V ZZ = = rms I 21.35 0 1 2 f LC = , so 0 1 4 C f L = For ( ) 5 z 5.00 10 = × 00 min 500 kH Hz ff ( ) 8 6 5.1 10
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