Mirrors and Lenses283(b) If f=−, then 12.0 cm()1112.0cpM−m1.00M⇒24.0 cmp( )1.00 =+⇒0 object is against the lensMp=Note that in both cases, Mapproaches +1.00 only in the limit as papproaches zero. Note also in part (b), the object must be virtual to obtain 1.00M= −. 23.31From the thin lens equation, 111pqf+=, the image distance is found to be ( )( )20.0 cm20.0 cm20.0 cm20.0 cmppfpqpf pp−===−−−−+(a) If 40.0p=, then and cm13.3 cmq( )13.3 cm1340.0 cmqMp−
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.