17_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

17_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 283 (b) If f =− , then 12.0 cm () 1 11 2 . 0 c p M    m 1.00 M 24.0 cm p ( ) 1.00 =+ 0 object is against the lens Mp = Note that in both cases, M approaches +1.00 only in the limit as p approaches zero. Note also in part (b), the object must be virtual to obtain 1.00 M = − . 23.31 From the thin lens equation, 111 p qf + = , the image distance is found to be ( ) ( ) 20.0 cm 20.0 cm 20.0 cm 20.0 cm p p fp q pf p p == = −− + (a) If 40.0 p = , then and cm 13.3 cm q ( ) 13.3 cm 13 40.0 cm q M p
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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