17_Ch 25 College Physics ProblemCH25 Optical Instruments

17_Ch 25 College Physics ProblemCH25 Optical Instruments -...

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Optical Instruments 353 The thin lens equation then gives the object distance for the objective as ( )( ) 11 1 4.30 cm 50.0 cm 3.94 cm 4.30 cm 50.0 cm qf p == = + −− The magnification by the objective is then ( ) 1 1 1 4.30 cm 1.09 3.94 cm q M p =− =+ and the overall magnification is ( )( ) 1 1.09 1.75 1.90 e mMm ++= 25.32 The angular resolution needed is 7 min 8 300 m 7.9 10 rad 3.8 10 m s r θ = × × For a circular aperture min 1.22 D λ = so 9 min m 1.22 0.77 m rad D  =  7 500 10 1.22 7.9 10 × × (about 30 inches)
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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