192
CHAPTER 20
20.47
(
)
(
)
2
2
3
1
1
70.0
10
H
2.00 A
0.140 J
2
2
L
PE
LI
−
=
=
×
=
20.48
(a)
The inductance of a solenoid is given by
2
0
L
N A
µ
=
l
, where
N
is the number of
turns on the solenoid,
A
is its crosssectional area, and
is its length. For the given
solenoid,
l
(
)
(
)
(
)
(
)
2
2
2
2
7
2
0
3
4
10
T
m
A
300
5.00
1
m
4.44
10
H
0.200 m
N
r
L
µ
π
π
π
−
×
⋅
=
=
=
×
l
0
−
−
×
(b)
When the solenoid described above carries a current of
0.500 A
I
=
, the stored
energy is
(
)
(
)
2
2
3
1
1
4.44
10
H
0.500 A
5.55
10
2
2
L
PE
LI
−
−
=
=
×
=
×
4
J
20.49
The current in the circuit at time
t
is
(
1
t
I
e
R
)
τ
ε
−
=
−
, and the energy stored in the
inductor is
2
1
2
L
LI
=
PE
(a) As
t
,
→∞
max
24 V
3.0 A
8.0
I
I
R
ε
→
=
=
=
Ω
, and
(
)(
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 Fall '10
 STAFF
 Physics, Inductance, Energy, Inductor, total resistance, Series and parallel circuits, PEL

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