18_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

# 18_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

This preview shows page 1. Sign up to view the full content.

250 CHAPTER 22 22.34 When surrounded by air ( , the critical angle of a material is ) 2 1.00 n = 11 1 in material nn −−    2 1 sin s c n θ == (a) For diamond, 1 1 sin 24.4 2.419 c ° (b) For flint glass, 1 1 sin 37.0 1.66 c ° 22.35 When surrounded by water ( ) 2 1.333 n = , the critical angle of a material is 2 1 sin sin c n 1.333 material (a) For diamond, 1 1.333 sin 33.4 2.419 c ° (b) For flint glass, 1 1.333 sin 53.4 1.66 c ° 22.36 Using Snell’s law, the index of refraction of the liquid is found to be ( ) 1.00 sin30.0 sin 1.33 sin sin22.0 air i liquid r n n ° = ° Thus, 1.00 sin sin 48.5 1.33 air c liquid n n === ° 1 22.37 When light attempts to cross a boundary from one medium of refractive index into a new medium of refractive index n 1 n 2 n < , total internal reflection will occur if the angle of
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online