18_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

18_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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284 CHAPTER 23 23.32 Comparing the given equation to the thin lens equation, 111 p qf + = , we see that the lens is a convergent lens ( ) 0 f > with focal length 7.50 cm f = . Also, the image distance is negative ( ) 3.50 q =− p , meaning the image is virtual. The lateral magnification is 3.50 qp pp =+ 3.50 M so the image is upright and enlarged. (a) Using the information deduced above, the thin lens equation becomes 11 1 3.50 7.50 cm −= giving () 1 7.50 cm 1 5.36 cm 3.50  = +   p (b) The image distance is then 3.50 5.36 cm 18.8 cm q = − (c) See the ray diagram at the right. ± ²³ (d) A simple magnifier is a device that uses a convergent lens to form an upright, enlarged, virtual image of a real object. One possible problem whose solution would
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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