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19_Ch 18 College Physics ProblemCH18 Direct-Current Circuits

19_Ch 18 College Physics ProblemCH18 Direct-Current...

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Direct-Current Circuits 117 (b) The total power input to the circuit is ( ) ( )( ) 1 2 1.50 V 1.50 V 0.600 A 1.80 W input I ε ε = + = + = P ( ) ( ) ( ) 2 2 1 2 0.600 A 0.255 0.153 0.147 loss I r r = + = Ω + Ω = P Thus, the fraction of the power input that is dissipated internally is W 0.147 W 0.081 6 or 8.16% 1.80 W loss input = = P P 18.25 Applying Kirchhoff’s junction rule at junction a gives (1) Using Kirchhoff’s loop rule on the upper loop yields
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