19_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

19_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Reflection and Refraction of Light 251 22.38 The critical angle for this material in air is 11 1.00 sin sin 47.3 1.36 air c pipe n n θ −−  ===   90.0 42.7 rc ° Thus, and from Snell’s law, ( ) 1.36 sin42.7 sin 67.2 1.00 ° == sin sin pipe r i air n n = ° 22.39 The light must be totally reflecting from the surface of a hot air layer just above the road surface. The angle of reflection, and hence the critical angle, is 90.0 1.20 88.8 c = °− °= ° . Thus, from 2 1 sin c n n = ( , we find ) 21 sin 1.000 3 sin88.8 1.000 08 c nn ° = 22.40 The circular raft must cover the area of the surface through which light from the diamond could emerge. Thus, it must form the base of a cone (with apex at the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online