20_Ch 18 College Physics ProblemCH18 Direct-Current Circuits

# 20_Ch 18 College Physics ProblemCH18 Direct-Current...

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118 CHAPTER 18 18.26 Using Kirchhoff’s loop rule on the outer perimeter of the circuit gives ( ) ( ) 13 12 V 0.01 0.06 0 II +− = 3 6 1.2 10 A +=× or (1) For the rightmost loop, the loop rule gives ( ) ( ) 23 10 V 1.00 0.06 0 ++ = 0.06 10 A −= 123 III =+ or (2) Applying Kirchhoff’s junction rule at either junction gives (3) Solving equations (1), (2), and (3) simultaneously yields ( ) 2 and 1.7 10 A (in starter) == × 0.28 A in dead battery 18.27 Assume currents in the directions shown. Then, using Kirchhoff’s junction rule at junction a gives (1) Applying Kirchhoff’s loop rule on the upper loop, 12 3 , , and I 2 I (
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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