20_Ch 19 College Physics ProblemCH19 Magnetism

20_Ch 19 College Physics ProblemCH19 Magnetism - 160...

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160 CHAPTER 19 (d) The cable creates zero field at exterior points, since a loop in Ampère’s law encloses zero total current. 19.44 (a) ( )( ) () 2 7 012 4 41 0 T m A 1 0 . 0 A 22 0 . 1 0 0 m 2.00 10 N m attraction II F Ld π µ ππ ×⋅ == (b) The magnitude remains the same as calculated in (a), but the wires are repelled. Thus, 4 2.00 10 N m repulsion F L 19.45 In order for the system to be in equilibrium, the repulsive magnetic force per unit length on the top wire must equal the weight per unit length of this wire. Thus, 0.080 N m 2 F , and the distance between the wires will be ( )( )( ) 7 3 4 10 T m A 60.0 A 30.0 A 2 0.080 N m 2 0.080 N m 4.5 10 m 4.5 mm d = 19.46 The magnetic forces exerted on the top and bottom segments of the rectangular loop are
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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