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20_Ch 19 College Physics ProblemCH19 Magnetism

# 20_Ch 19 College Physics ProblemCH19 Magnetism - 160...

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160 CHAPTER 19 (d) The cable creates zero field at exterior points, since a loop in Ampère’s law encloses zero total current. 19.44 (a) ( ) ( ) ( ) ( ) 2 7 0 1 2 4 4 10 T m A 10.0 A 2 2 0.100 m 2.00 10 N m attraction I I F L d π µ π π × = = = × (b) The magnitude remains the same as calculated in (a), but the wires are repelled. Thus, ( ) 4 2.00 10 N m repulsion F L = × 19.45 In order for the system to be in equilibrium, the repulsive magnetic force per unit length on the top wire must equal the weight per unit length of this wire. Thus, 0 1 2 0.080 N m 2 I I F L d µ π = = , and the distance between the wires will be ( ) ( ) ( )( ) ( ) 7 0 1 2 3 4 10 T m A 60.0 A 30.0 A 2 0.080 N m 2 0.080 N m 4.5 10 m 4.5 mm I I d π µ π π × = = = × = 19.46 The magnetic forces exerted on the top and bottom segments of the rectangular loop are
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