21_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

21_Ch 21 College Physics ProblemCH21 Alternating Current Circuits and Electromagnetic Waves

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Alternating Current Circuits and Electromagnetic Waves 221 21.41 (a) At 90% efficiency, () ( ) av av 0.90 output input = PP 1000 kW = Thus, if the input power to the primary is av output P ( ) av 3 1.1 10 kW 0.90 0.90 output === × P av input P (b) 36 av 2 1, rms 1, rms 1, rms 1.1 1.1 10 W 3.1 10 A 3 600 V input VV ×× = = × ∆∆ P I == (c) 6 av 3 2,rms 1,rms 1.0 8.3 120 V output × = = × P I 21.42 ( )( ) 45 4.50 10 m 6.44 10 m 290 line R =×Ω × =Ω (a) The power transmitted is ( ) ( ) av rms rms transmitted VI =∆ P so 6 3 0 10.0 A 0 10 V × = ∆× av rms rms 5.0 50 transmitted I V P Thus, 2 10.0 A 290 2.90 1 =
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