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21_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

# 21_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

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Reflection and Refraction of Light 253 22.43 If c 42.0 θ = ° at the boundary between the prism glass and the surrounding medium, then 2 1 sin c n n θ = gives sin 42.0 = ° m glass n n or 1 sin42.0 glass m n n ° 90.0 42.0 1.494 = = 48.0 , From the geometry shown in the above figure, 180 60.0 72.0 α β α ° = ° − ° − = = ° − 90.0 18.0 ° = ° and r θ β = ° − = ° . Thus, applying Snell’s law at the first surface gives ( ) 1 1 1 sin sin sin 1.494 sin18.0 27.5 glass r m n n θ θ

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21_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

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