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Mirrors and Lenses
287
(b) If
4.00
p
=
, then
and
m
1.00 m
q
=
1.00 m
1
4.00 m
4
q
M
p
=
−=
−
=
−
In this case, the image is
real, in
4.00 m
q
=
verted, and onequarter the size of the object
If
, then
and
1.00 m
p
=
4.00 m
4
1.00 m
q
M
p
=
−
=
−
. In this case, the image
is
real, inverted,
mes th
and four ti
e size of the object
23.39
Since the light rays incident to the first lens are parallel,
1
p
=
∞
and the thin lens
equation gives
.
The virtual image formed by the first lens serves as the object for the second lens, so
11
10.0 cm
qf
==
−
2
30.0 cm
p
=+
2
q
=
∞
1
40.0 cm
q
=
. If the light rays leaving the second lens are parallel, then
and the thin lens equation gives
22
40.0 c
fp
m .
23.40
With
p
and
, the thin lens equation gives the position of the
image formed by the first lens as
1
20.0 cm
=
1
25.0 cm
f
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics

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