56CHAPTER 16 16.40The original circuit reduces to a single equivalent capacitor in the steps shown below. 111211113.33 F5.00 F10.0 FsCCCµµµ−−=+=+=()132 3.33 F2.00 F8.66 FpssCCCCµµµ=++=+=()2222 10.0 F20.0 FpCCCµµ=+==111211116.04 F8.66 F20.0 FeqppCCCµµµ−−=+=+=16.41Refer to the solution of Problem 16.40 given above. The total charge stored between points aand bis ()()()6.04 F60.0 V362 CeqeqabQCVµµ=∆==12362 CppeqQQQThen, looking at the third figure, observe that the charges of the series capacitors of that
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