22_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

22_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
56 CHAPTER 16 16.40 The original circuit reduces to a single equivalent capacitor in the steps shown below. ± ² ³ ± ³ ± ³ ´ ³ ´ ³ ² ³ µ ± ³ µ ³ ± ² ³ ¶· ± ² ± ² ³ ± ³ ± ³ ³ ³ ² ³ ³ ³ ± ³ ± 1 1 12 11 1 1 3.33 F 5.00 F 10.0 F s C CC µ µµ  =+ = + =   ( ) 13 2 3.33 F 2.00 F 8.66 F ps s CCCC =++= + = ( ) 222 2 10.0 F 20.0 F p CCC =+= = 1 1 1 1 6.04 F 8.66 F 20.0 F eq pp C = + = 16.41 Refer to the solution of Problem 16.40 given above. The total charge stored between points a and b is ( ) ( )( ) 6.04 F 60.0 V 362 C eq eq ab QC V =∆= = 362 C ppe q QQQ Then, looking at the third figure, observe that the charges of the series capacitors of that
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online