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22_Ch 18 College Physics ProblemCH18 Direct-Current Circuits

# 22_Ch 18 College Physics ProblemCH18 Direct-Current...

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120 CHAPTER 18 18.29 Applying Kirchhoff’s junction rule at junction a gives (1) Using Kirchhoff’s loop rule on the leftmost loop yields 3 1 I I I = + ( 2 ) ( ) 3 1 4.00 5.00 12.0 V 0 I I + 9.00 A ( ) ( 3.00 V 1 3 5 4 I I + = = or (2) and for the rightmost loop, ) 3 2 4.00 3.00 2.00 18.0 I I + + 15.0 A 1 2 3 A, 1.523 A, and 1.846 A I I I = = = 3.00 V 2 3 5 4 I I + = 0.323 ( V 0 = or (3) Solving equations (1), (2), and (3) simultaneously gives Therefore, the potential differences across the resistors are ) 2 2 2 V I = .00 3.05 V Ω = , ( ) 3 2 3.00 4.5 V I = 7 V = ( ) 4 3 4 V I = .00 7.3 8 V = , and ( ) 5 1 5 V I = .00 1.62 V Ω = 18.30
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