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288
CHAPTER 23
23.41
The thin lens equation gives the image position for the first lens as
()
( )
11
1
30.0 cm
15.0 cm
30.0 cm
30.0 cm
15.0 cm
pf
q
==
=
+
−−
and the magnification by this lens is
1
1
1
30.0 cm
1.00
30.0 cm
q
M
p
=−
The real image formed by the first lens serves as the object for the second lens, so
. Then, the thin lens equation gives
21
40.0 cm
10.0 cm
pq
=
+
( )( )
22
2
10.0 cm
15.0 cm
30.0 cm
10.0 cm
15.0 cm
q
=
−
and the magnification by the second lens is
( )
2
2
2
30.0 cm
3.00
10.0 cm
q
M
p
−
=+
Thus, the final, virtual image is located
30.0 cm in front of the second lens
and the overall magnification is
( )( )
12
1.00
3.00
3.00
M
−+
=
−
MM
23.42
(a) With
p
, the thin lens equation gives the position of the image formed
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics

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