22_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

# 22_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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288 CHAPTER 23 23.41 The thin lens equation gives the image position for the first lens as () ( ) 11 1 30.0 cm 15.0 cm 30.0 cm 30.0 cm 15.0 cm pf q == = + −− and the magnification by this lens is 1 1 1 30.0 cm 1.00 30.0 cm q M p =− The real image formed by the first lens serves as the object for the second lens, so . Then, the thin lens equation gives 21 40.0 cm 10.0 cm pq = + ( )( ) 22 2 10.0 cm 15.0 cm 30.0 cm 10.0 cm 15.0 cm q = and the magnification by the second lens is ( ) 2 2 2 30.0 cm 3.00 10.0 cm q M p =+ Thus, the final, virtual image is located 30.0 cm in front of the second lens and the overall magnification is ( )( ) 12 1.00 3.00 3.00 M −+ = MM 23.42 (a) With p , the thin lens equation gives the position of the image formed
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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