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Current and Resistance
91
17.53
(a) The total power you now use while cooking breakfast is
( )
1200
500 W
1.70 kW
=+
=
P
() ( )
The cost to use this power for 0.500 h each day for 30.0 days is
()
h
00
30.0 days
$0.120 kWh
$3.06
day
cost
=
1.70 kW
0.5
t
rate
=×
∆× =
P
(b) If you upgraded, the new power requirement would be:
( )
2 400
500 W=2 900 W
P
and the required current would be
2 900 W
26.4 A
20 A
110 V
I
V
==
=
>
∆
P
No , your present circuit breaker cannot handle the upgrade.
17.54
(a) The charge passing through the conductor in the interval
is represented by the area under the
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics, Current, Resistance, Power

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