23_Ch 19 College Physics ProblemCH19 Magnetism

23_Ch 19 College Physics ProblemCH19 Magnetism - 163...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Magnetism 163 (b) The radius of the semicircular path is 2.00 cm. From rm v q B = , the momentum of the electron is p = mv = qBr , and the kinetic energy is () ( ) ( ) 22 2 19 2 2 222 2 1 2 31 1.60 10 C 0.010 0 T 2.00 10 m 29 .11 10 kg mv qBr KE mv mm −− ×× == = = × 16 16 1 keV 5.62 10 J 3.51 keV 1.60 10 J KE  =  ×  19.53 Assume wire 1 is along the x axis and wire 2 along the y axis. (a) Choosing out of the page as the positive field direction, the field at point P is ( ) 7 0 12 7 41 0 T m A 5.00 A 3.00 A 2 2 0.400 m 0.300 m 5.00 10 T 0.500 T out of the page II BB B rr π µ ππ ×⋅ =−= − = = (b) At 30.0 cm above the intersection of the wires, the field components are as shown at the right, where 01 1 7 6 2 0 T m A 5 . 0 0 A 3.33 10 T 20 . 3 0 0 m
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online