Magnetism163(b) The radius of the semicircular path is 2.00 cm. From rmvqB=, the momentum of the electron is p = mv = qBr, and the kinetic energy is ()( )( )2221922222212311.6010C0.010 0 T2.0010m29.11 10 kgmvqBrKEmvmm−−−××== = =×16161 keV5.6210J3.51 keV1.6010JKE−−=×=×19.53Assume wire 1 is along the xaxis and wire 2 along the yaxis. (a) Choosing out of the page as the positive field direction, the field at point Pis ( )70127410TmA5.00 A3.00 A220.400 m0.300 m5.0010T0.500 T out of the pageIIBB Brrπµππ−−×⋅=−=− =−=(b) At 30.0 cm above the intersection of the wires, the field components are as shown at the right, where 0117620TmA5.00A3.3310T20.300m
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.