23_Ch 19 College Physics ProblemCH19 Magnetism

# 23_Ch 19 College Physics ProblemCH19 Magnetism - 163...

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Magnetism 163 (b) The radius of the semicircular path is 2.00 cm. From rm v q B = , the momentum of the electron is p = mv = qBr , and the kinetic energy is () ( ) ( ) 22 2 19 2 2 222 2 1 2 31 1.60 10 C 0.010 0 T 2.00 10 m 29 .11 10 kg mv qBr KE mv mm −− ×× == = = × 16 16 1 keV 5.62 10 J 3.51 keV 1.60 10 J KE  =  ×  19.53 Assume wire 1 is along the x axis and wire 2 along the y axis. (a) Choosing out of the page as the positive field direction, the field at point P is ( ) 7 0 12 7 41 0 T m A 5.00 A 3.00 A 2 2 0.400 m 0.300 m 5.00 10 T 0.500 T out of the page II BB B rr π µ ππ ×⋅ =−= − = = (b) At 30.0 cm above the intersection of the wires, the field components are as shown at the right, where 01 1 7 6 2 0 T m A 5 . 0 0 A 3.33 10 T 20 . 3 0 0 m
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