23_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

23_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Reflection and Refraction of Light 255 (b) Repeating the steps of part (a) with the index of refraction of air replaced by that of water yields 3 63.5 θ ≥° , 2 26.5 ≤° , 1 sin 0.499 , and 1 30.0 . (c) Total internal reflection is not possible since polystyrene carbon disulfide nn < 22.47 Applying Snell’s law at points A, B, and C, gives 1 1.40sin 1.60sin αθ = (1) 1.20sin 1.40sin β α = (2) and 2 1.00sin 1.20sin = (3) Combining equations (1), (2), and (3) yields 21 sin 1.60sin θθ = (4) Note that equation (4) is exactly what Snell’s law would yield if the second and third layers of this “sandwich” were ignored. This will always be true if the surfaces of all the layers are parallel to each other. (a) If 1 30.0 , then equation (4) gives () 1 2 sin 1.60sin30.0 53.1 = ° (b) At the critical angle of incidence on the lowest surface,
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online