24_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

# 24_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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58 CHAPTER 16 16.45 The capacitance of this parallel plate capacitor is ( ) () 62 2 12 0 2 1.0 10 m C 8.85 10 N m 800 m A C d ×  =∈ = × =   8 1.1 10 F × With an electric field strength of 6 3.0 10 N C E and a plate separation of d , the potential difference between plates is 800 m = ( ) 69 3.0 10 V m 800 m 2.4 10 V VE d ∆= = × = × Thus, the energy available for release in a lightning strike is 2 89 0 F 2.4 × × 2 11 1.1 1 22 WCV =∆= 1 0 3.2 10 J 16.46 The energy transferred to the water is ( )( ) 8 7 50.0 C 1.00 2.50 10 J 100 2 200 WQ V ×  =∆ = = ×   v Wm cT L + Thus, if m is the mass of water boiled away, becomes 7 2.50 418 m ×= 6 J 100 C 30.0 C 2.26 10 J kg kg C ° ° ⋅° giving 7 2.50
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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