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290
CHAPTER 23
23.44
(a) We start with the final image and work backward. From Figure P22.44, observe that
( )
2
50.0 cm
31.0 cm
19.0 cm
q
=−
−
. The thin lens equation
then gives
( )( )
22
2
19.0 cm
20.0 cm
9.74 cm
19.0 cm
20.0 cm
qf
p
−
==
=
+
−−
−
9.74 cm
40.3 cm
=−=
The image formed by the first lens serves as the object for the second lens and is
located 9.74 cm in front of the second lens.
Thus,
and the thin lens equation gives
1
50.0 cm
q
( )( )
11
40.3 cm
10.0 cm
40.3 cm
10.0 cm
1
13.3 cm
p
=
+
The original object should be located
13.3 cm in front of the first lens.
(b) The overall magnification is
( )
12
19.0 cm
40.3 cm
5.90
13.3 cm
9.74 cm
qq
MMM
pp
−
−
−
=
−
−
=
−
(c) Since
0
M
<
, the final image is
inverted ;
and since
, it is
2
q
0
<
virtual
23.45
Since the final image is to be real and in the film plane,
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics, Work

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