290CHAPTER 23 23.44(a) We start with the final image and work backward. From Figure P22.44, observe that ( )250.0 cm31.0 cm19.0 cmq=−−. The thin lens equation then gives ( )( )22219.0 cm20.0 cm9.74 cm19.0 cm20.0 cmqfp−===+−−−9.74 cm40.3 cm=−=The image formed by the first lens serves as the object for the second lens and is located 9.74 cm in front of the second lens. Thus, and the thin lens equation gives 150.0 cmq( )( )1140.3 cm10.0 cm40.3 cm10.0 cm113.3 cmp=+The original object should be located 13.3 cm in front of the first lens. (b) The overall magnification is ( )1219.0 cm40.3 cm5.9013.3 cm9.74 cmqqMMMpp−−−=−−=−(c) Since 0M<, the final image is inverted ; and since , it is 2q0<virtual 23.45Since the final image is to be real and in the film plane,
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.