25_Ch 18 College Physics ProblemCH18 Direct-Current Circuits

25_Ch 18 College Physics ProblemCH18 Direct-Current...

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Direct-Current Circuits 123 18.38 (a) The equivalent resistance of the parallel combination is 1 1 123 111 1 1 1 15 150 25 50 eq R RRR  =++ = + + =  ΩΩΩ  so the total current supplied to the circuit is 120 V 8.0 A 15 total eq V I R == = (b) Since the appliances are connected in parallel, the voltage across each one is 120 V V ∆= . (c) 120 V 0.80 A 150 lamp lamp V R = I (d) () 22 2 120 V 5.8 10 W 25 heater heater V R = × P 18.39 From 2 VR =∆ P , the resistance of the element is 240 V 19.2 3000 W V R = P When the element is connected to a 120-V source, we find that
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