Mirrors and Lenses
291
From the thin lens equation,
( )
1
11
1
11 1
15.0 cm
15.0 cm
q
qf
p
qfq
==
−−
When
1
15.1 cm
q
=+
( )
5.00
d
=
(
cm
3
1
1.82
10
p
=×
, then
When
cm
18.2 m
=
1
45.3 cm
q
)
10
d
=
.0 cm
1
22.4 cm
p
, then
0.224 m
=
=
Thus, the range of focal distances for this camera is
0.224 m to 18.2 m
23.46
Consider an object
O
at distance
in
front of the first lens. The thin lens equation
gives the image position for this lens as
1
1
p
111
qfp
=−
1
1
q
.
±
±
²
²
±
²
³
±
³
³
²
³´³
²
±
³
´
±
³´³µ
µ
²
´
²
µ
±
The image,
I
, formed by the first lens serves as the object,
O
, for the second lens. With
the lenses in contact, this will be a virtual object if
is real and will be a real object if
is virtual. In either case, if the thicknesses of the lenses may be ignored,
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics

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