25_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

25_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 291 From the thin lens equation, ( ) 1 11 1 11 1 15.0 cm 15.0 cm q qf p qfq == −− When 1 15.1 cm q =+ ( ) 5.00 d = ( cm 3 1 1.82 10 p , then When cm 18.2 m = 1 45.3 cm q ) 10 d = .0 cm 1 22.4 cm p , then 0.224 m = = Thus, the range of focal distances for this camera is 0.224 m to 18.2 m 23.46 Consider an object O at distance in front of the first lens. The thin lens equation gives the image position for this lens as 1 1 p 111 qfp =− 1 1 q . ± ± ² ² ± ² ³ ± ³ ³ ² ³´³ ² ± ³ ´ ± ³´³µ µ ² ´ ² µ ± The image, I , formed by the first lens serves as the object, O , for the second lens. With the lenses in contact, this will be a virtual object if is real and will be a real object if is virtual. In either case, if the thicknesses of the lenses may be ignored,
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