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26_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

26_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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60 CHAPTER 16 16.51 (a) 12 16 3 3 1.00 10 kg 9.09 10 m 1100 kg m m ρ × = = = × V Since 3 4 3 r V π = , the radius is 1 3 3 4 V r π = , and the surface area is ( ) 2 3 16 3 2 3 10 2 m 3 4.54 10 m V = = × 2 4 4 A r π π = = 3 9.09 10 4 4 4 π π π × (b) 0 A C = d κ ( ) ( )( ) 12 2 2 10 2 13 9 5.00 8.85 10 C N m 4.54 10 m 2.01 10 F 100 10 m × × = = × × (c) ( ) ( )( ) 13 -3 14 2.01 10 F 100 10 V 2.01 10 C V = = × × = × Q C and the number of electronic charges is 14 5 -19 2.01 10 C 1.26 10 1.60 10 C Q n e × = = = × × 16.52 Since the capacitors are in parallel, the equivalent capacitance is
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