26_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

26_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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60 CHAPTER 16 16.51 (a) 12 16 3 3 1.00 10 kg 9.09 10 m 1100 kg m m ρ × == = × V Since 3 4 3 r V π = , the radius is 13 3 4 V r = , and the surface area is () 23 16 3 10 2 m 3 4 . 5 4 1 0 m V   =  2 44 Ar ππ 39 .09 10 4 × (b) 0 A C = d κ ( )( ) 12 2 2 10 2 13 9 5.00 8.85 10 C N m 4.54 10 m 2.01 10 F 100 10 m −− ×⋅ × × × (c) ( ) 13 -3 14 2.01 10 F 100 10 V 2.01 10 C V =∆= × × = × QC and the number of electronic charges is 14 5 -19 2.01 10 C 1.26 10 1.60 10 C Q n e × = × × 16.52 Since the capacitors are in parallel, the equivalent capacitance is ( ) 01 2 3 01 02 03
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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