26_Ch 17 College Physics ProblemCH17 Current and Resistance

26_Ch 17 College Physics ProblemCH17 Current and Resistance...

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94 CHAPTER 17 (c) The filament is tightly coiled to fit the required length into a small space (d) From ( ) 00 1 TT α  =+−  LL , where () 1 6 4.5 10 C ° , the length at is 0 20 C T 0 0 25 m 1 1 4.5 10 C L L == = +− ° 1 6 26 m C 2 600 C 20 ° ° 17.60 Each speaker has a resistance of 4.00 R = and can handle 60.0 W of power. From , the maximum safe current is 2 IR = P max 60.0 W 4.00 R 3.87 A = I Thus, the system is not adequately protected by a 4.00 A fuse. 17.61 The cross-sectional area of the conducting material is ( ) 22 outer inner Arr π =− Thus, ( )( ) ( ) 52 3.5 10 m 4.0 10 m 1 . 21 0 m 0 . 5 01 L R A ρ −− ×Ω × ×− ×  7 3.7 37 M =×Ω = 17.62 (a)
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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