94CHAPTER 17 (c) The filament is tightly coiled to fit the required length into a small space (d) From ( )001TTα=+−LL, where ()164.510C−−=×°, the length at is 020 CT=°0025 m114.510CLL−===+−+×°1626 mC2 600 C20−°°−17.60Each speaker has a resistance of 4.00 R=Ωand can handle 60.0 W of power. From , the maximum safe current is 2IR=Pmax60.0 W4.00 RΩ√3.87 A=IThus, the system is not adequately protected by a 4.00 A fuse. 17.61The cross-sectional area of the conducting material is ( )22outerinnerArrπ=−Thus, ( )( )( )523.510 m4.010m1.210 m0.501LRAρ−−−×Ω⋅×Ω×−×73.737 M=×Ω=17.62(a)
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.