26_Ch 17 College Physics ProblemCH17 Current and Resistance

26_Ch 17 College Physics ProblemCH17 Current and Resistance...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
94 CHAPTER 17 (c) The filament is tightly coiled to fit the required length into a small space (d) From ( ) 00 1 TT α  =+−  LL , where () 1 6 4.5 10 C ° , the length at is 0 20 C T 0 0 25 m 1 1 4.5 10 C L L == = +− ° 1 6 26 m C 2 600 C 20 ° ° 17.60 Each speaker has a resistance of 4.00 R = and can handle 60.0 W of power. From , the maximum safe current is 2 IR = P max 60.0 W 4.00 R 3.87 A = I Thus, the system is not adequately protected by a 4.00 A fuse. 17.61 The cross-sectional area of the conducting material is ( ) 22 outer inner Arr π =− Thus, ( )( ) ( ) 52 3.5 10 m 4.0 10 m 1 . 21 0 m 0 . 5 01 L R A ρ −− ×Ω × ×− ×  7 3.7 37 M =×Ω = 17.62 (a)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online