26_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

26_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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292 CHAPTER 23 23.47 Since q =+ when , we find that 8.00 cm 10.0 cm p 1 1 1 fpq =+= 20.0 p = 1 18.0 10.0 cm 80.0 cm cm 1 8.00 cm + = Then, when , 1 1 1 qfp 18.0 80.0 c 1 m 20.0 cm 18.0 4.00 14.0 80.0 cm 80.0 cm =−= = = or 80.0 cm 14.0 == 5.71 cm + q Thus, a real image is formed 5.71 cm in front of the mirror 23.48 Applying the thin lens equation to the first lens gives ( )( ) () 11 1 12 cm 6.0 cm 4.0 cm 12 cm 6.0 cm pf q = −− The virtual image formed by the first lens serves as the object for the second lens. If the image formed by that converging lens is to be located at infinity, the image formed by the diverging lens must be located at the focal point in front of the converging lens.
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