26_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

26_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
292 CHAPTER 23 23.47 Since q =+ when , we find that 8.00 cm 10.0 cm p 1 1 1 fpq =+= 20.0 p = 1 18.0 10.0 cm 80.0 cm cm 1 8.00 cm + = Then, when , 1 1 1 qfp 18.0 80.0 c 1 m 20.0 cm 18.0 4.00 14.0 80.0 cm 80.0 cm =−= = = or 80.0 cm 14.0 == 5.71 cm + q Thus, a real image is formed 5.71 cm in front of the mirror 23.48 Applying the thin lens equation to the first lens gives ( )( ) () 11 1 12 cm 6.0 cm 4.0 cm 12 cm 6.0 cm pf q = −− The virtual image formed by the first lens serves as the object for the second lens. If the image formed by that converging lens is to be located at infinity, the image formed by the diverging lens must be located at the focal point in front of the converging lens.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online