27_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

# 27_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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Electrical Energy and Capacitance 61 16.54 For the parallel combination: CC 1 p C 2 = + which gives (1) For the series combination: 2 p CCC =− 1 1 1 1 s C C = 12 111 =+ 2 or ss s Thus, we have 1 s 2 1 s C = and equating this to Equation (1) above gives 1 1 1 s p s −= or 2 11 s s C + 1 pp −− 1 s = We write this result as : 2 0 s C += and use the quadratic formula to obtain 2 1 24 p s C C C Then, Equation (1) gives 2 2 p s C C C 16.55 The charge stored on the capacitor by the battery is ( ) ( ) 1 100 V QC V C =∆ = This is also the total charge stored in the parallel combination when this charged capacitor is connected in parallel with an uncharged 10.0- F µ capacitor. Thus, if ( ) 2 V is the resulting voltage across the parallel combination, ( ) 2 V p QC = gives ( ) ( )( )
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