Electrical Energy and Capacitance6116.54 For the parallel combination: CC1pC2=+which gives (1) For the series combination: 2pCCC=−1111sCC−=12111=+2or sssThus, we have 1s21sC=−and equating this to Equation (1) above gives 111sps−=−or 211ssC+1pp−−1s=We write this result as : 20sC−+=and use the quadratic formula to obtain 2124psCCC=±−Then, Equation (1) gives 22psCCC∓16.55 The charge stored on the capacitor by the battery is ( ) ( )1100 VQC VC=∆ =This is also the total charge stored in the parallel combination when this charged capacitor is connected in parallel with an uncharged 10.0- Fµcapacitor. Thus, if ( )2V∆is the resulting voltage across the parallel combination, ( )2VpQC=∆gives ( ) ( )( )
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.